Math, asked by PrayagJain2, 9 months ago

If the sum of the first p terms of an AP is the same as the sum of its
first q terms (where p is not equal to q) then show that the sum of its first (p+q)
terms is zero.​

Answers

Answered by richapaul
1

Answer:

Its there in RD Sharma.

Or you can also refer to RS Agarwal. There is step by step explanation for students

Attachments:
Answered by Anonymous
0

{\green {\boxed {\mathtt {✓verified\:answer}}}}

let \:  \: a \:  \: be \: the \: first \: term \: and \: d \: be \: the \: common \: difference \: of \: the \: given \: ap \: \\ then \\ s _{p} = s _{q}  \implies \frac{p}{2} (2a + (p - 1)d) =  \frac{q}{2} (2a + (q - 1)d \\  \implies(p - q)(2a)  = (q - p)(q + p - 1) \\  \implies2a = (1 - p - q)d \:  \:  \:  \:  \:  \:  \: .....(1) \\ sum \: of \: the \: first \: (p + q) \: terms \: of \: the \: given \: ap \\  =  \frac{(p  + q)}{2} (2a + (p + q - 1)d) \\  =  \frac{(p + q)}{2} .(1 - p - q)d + (p + q - 1)d \:  \:  \:  \:  \:  \:  \:  \: (using \: 1) \\   = 0

{\huge{\underline{\underline{\underline{\orange{\mathtt{❢◥ ▬▬▬▬▬▬ ◆ ▬▬▬▬▬▬ ◤❢}}}}}}}

Similar questions