Question

if the sum of the first p terms of an arithmetic progression is ap²+bp, then find the common difference

Answer 1

Answer:

Common difference = [2(a - ap - b)]/(1-p)

Step-by-step explanation:

Sn = n/2(2a + (n-1)d)

Sp = p/2(2a + pd -d) = p(ap + b)

-> 2a + pd - d = 2ap + 2b

-> 2a + pd - 2ap - 2b = d

-> 2a - 2ap - 2b = d(1-p)

-> [2(a - ap - b)]/(1-p)=d

d = [2(a - ap - b)]/(1-p)

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Answer 2

Hope, it helps u...