Question

if the sum of the first11 terms is 33 then find 6 th term​

Answer 1

11 terms = 33

1 term = 33/11

= 3

6 terms = 3 x 6

= 18

Therefore, the 6th term is 18

Answer 2

Given :-

• S₁₁ = 33

To find :-

• a₆

Solution :-

Let ,

first term of AP = a

common difference of AP = d

Given that

S₁₁ = 33

$\mathrm{ \frac{11}{2}(2a +(11 - 1))d = 33}$

$\mathrm{ \frac{11}{2}(2a + 10d) = 33 }$

$\mathrm{a + 5d = \frac{33}{11} }$

$\mathrm{a + 5d = 3\: ...eqn(1)}$

Now,

We have to find

a₆

a₆ = a + 5 d

Using eqn (1)

$\boxed{ \bf{ \pink{a_6 = 3}}}$