If the sum of the last two digits of a three- digit number is divisible by 9, what is the probab
ility of the number being divisible by 3?
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Step-by-step explanation:
Given 2x+3y=7 ... (i)
and 3x+2y=3 ... (ii)
On subtracting (ii) from (i) we get
2x+3y−3x−2y=7−3
⟹−x+y=4
⟹x−y=−4
Hence, the answer is −4.
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