If the sum of the Length, breadth and depth of a cuboid is 19 cm and its diagonal is 5√5 then find its surface area.
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l+b+h = 19cm ...........……………………………(i)
√l^2 + b^2 + h^2 = 5√5
squaring on both sides
l^2 + b^2 + h^2 = 125.………………………...(ii)
in (i),
squaring on both sides
l^2 + b^2 + h^2 +2lb+2bh+2hl = 361
125+2[lb+bh+hl] = 361
lb+bh+hl = 236/2
lb+bh+hl = 118
TSA = 2[lb+bh+hl]
= 236cm^2
please mark it as the brainliest answer
√l^2 + b^2 + h^2 = 5√5
squaring on both sides
l^2 + b^2 + h^2 = 125.………………………...(ii)
in (i),
squaring on both sides
l^2 + b^2 + h^2 +2lb+2bh+2hl = 361
125+2[lb+bh+hl] = 361
lb+bh+hl = 236/2
lb+bh+hl = 118
TSA = 2[lb+bh+hl]
= 236cm^2
please mark it as the brainliest answer
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