if the sum of the m terms of an AP is the same as the sum of its n terms , show that the sum of its (m+n)th term is 0
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given Sm=Sn or. m/2{2a+(m-1)d}=n/2{2a+(n-1)d} or m/n=(2a+(n-1)d)/(2a+(m-1)d) now S(m+n)= (m+n)/2{2a+(m+n-1)d}...by putting value of 'd' from above equations, we get S(m+n)=0...
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