If the sum of the number and its square is 132 then what is the number
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Let the number be x. Then its square is x2.
x2+x=132
x2+x−132=0
(x+12)(x−11)=0
x=−12and11
∴The number is either −12 or 11.
Hopefully this helps!
7
x2+x=132
x2+x−132=0
(x+12)(x−11)=0
x=−12and11
∴The number is either −12 or 11.
Hopefully this helps!
7
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