Question

If the sum of the parallel sides of the trapezium is 26cm whose area is 117 cm2 then what is distance between its parallel sides? 

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Answer 1

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→ Trapezium:

A trapezium is a quadrilateral having one pair of parallel opposite sides. In the given figure, ABCD is a trapezium in which AB ∥ DC.

Area of a Trapezium:

Let ABCD be a trapezium in which AB ∥ DC, CE ⊥ AB, DF ⊥ AB and CE = DF = h.

Prove that:

Area of a trapezium ABCD = {¹/₂ × (AB + DC) × h} square units.

Proof: Area of a trapezium ABCD

= area (∆DFA) + area (rectangle DFEC) + area (∆CEB)

= (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE)

= (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h)

= ¹/₂ × h × (AF + 2FE + EB)

= ¹/₂ × h × (AF + FE + EB + FE)

= ¹/₂ × h × (AB + FE)

= ¹/₂ × h × (AB + DC) square units.

= ¹/₂ × (sum of parallel sides) × (distance between them)

Formula of Area of a trapezium = ¹/₂ × (sum of parallel sides) × (distance between them)

♥️ Hope It Helps You

Answer 2

Answer:

the distance between them be