Question

if the sum of the root of the quadratic equation ax square + bx + c is equal to zero is equal to the sum of the square of their reciprocal, then prove that 2a square c =c square b + b square a

Answer 1

The roots of the equation r = - b/a nd c/a
-b/a+c/a=0---------(1)

And
(-b/a) ^2+(c/a)=0---------(2)

From (1)nd (2)
We get a=b=c

So substitute that u will get the ans

Answer 2

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