Question

If the sum of the roots of an equation is 6 and one root is 3-√5 , then the equation is: (a) x2 –6x+4 = 0 (b) x 2 –4x+6 = 0 (c) x 2 –6x+5 = 0 (d) None of these​

Answer 1

Answer:

Step-by-step explanation:

Let "a" and "b" be the roots.

a= 3-√5

Given

a+b=6

3-√5+b=6

b=6-(3-√5)

b=6-3+√5

b=3+√5

General form of an equation,

x²+(a+b)+ab

x²+3-√5+3+√5+(3-√5)(3+√5)

x²+6+9-5

x²+10

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Answer 2

Answer:

a

Step-by-step explanation:

if one root is 3-√5 then the other root is 3+√5 then sum of root is 3-√5+3+√5=6. product of root is 3-√5*3+√5=9-5=4. then the equation is x*2-6x+4