Question

If the sum of the roots of the equation 3x^2+kx+1 =0 is 7 then what is the value of k ?

Answer 1

Step-by-step explanation:

sum of the roots= (-k/3)=7

k= -21

Answer 2

Answer:

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Step-by-step explanation:

$so \: here \: given \: quadratic \: equation \: is \: 3x \: square + kx + 1 = 0$

$so \: let \: its \: two \: roots \: be \: \alpha \: and \: \beta$

$so \: here \: \alpha + \beta = 7$

$now \: comparing \: the \: quadratic \: equation \: with \: ax \: square + bx + c = 0$

$we \: get \\ a = 3 \: \: \: b = k \: \: c = 1$

$now \: we \: now \: that \: \\ \alpha + \beta = - b \div a$

$ie \: 7 = - k \div3 \\ ie \: - k = 21 \\ so \: k = - 21$

$hence \: value \: of \: k \: is \: - 21$