Question

If the sum of the roots of the equation (a + 1)x^2 + (2a + 3)x+ (3a + 4) = 0 is -1, find the product of the roots.​

Answer 1

Answer:

-1

Step-by-step explanation:

(a + 1)x^2 + (2a + 3)x+ (3a + 4) = 0

sum of roots=-1

(-1)=(-b)/a

(-1)= $\frac{-(2a+3)}{a+1}$

a+1=2a+3

2a-a=1-3

a=(-2)

putting 'a' in the quadratic equation:-

-x²+(-2+3)x+(-3+4)=0

-x²+x+1=0

   OR

x²-x-1=0

=>product of roots=$\frac{c}{a}$=$\frac{(-1)}{1}$=(-1)

Hope this helps you...