Question

If the sum of the roots of the equation kx(x-3)+2x-7=0 is 5 then the value of k is

Answer 1

Answer:

alpha +beeta =(-b/a) =5

Step-by-step explanation:

put the value and get the answer

Answer 2

The value of k is -1.

Explanation:

We know that ,

For a quadratic equation $ax^2+bx+c=0$  , the sum and the product of roots is

$S=\dfrac{-b}{a}, \ \ P=\dfrac{c}{a}$

Given quadratic equation : $kx(x-3)+2x-7=0$

$\Rightarrow\ kx^2-3kx+2x-7=0\\\\\Rightarrow\ kx^2+(2-3k)x-7=0$

here , a= k and b= 2-3k

If the sum of the roots is 5 , then

$\dfrac{-(2-3k)}{k}=5\\\\ 3k-2=5k\\\\ 5k-3k=-2\\\\ 2k=-2\\\\ k=-1$

Hence, the value of k is -1.

# Learn more :

Find the value of k in which x=3 is a root of equation( (kx)2)+2x-3=0

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