Question

If the sum of the roots of the equation x2+px+q=0 is 3 times their difference, then​

Answer 1

Answer:

x²+px+q = 0

let the roots be a and b. (a>b)

a+b = -p. (1)

According to question,

a+b = 3(a-b)

=>. -p. = 3(a-b)

=>. a-b = -p/3. (2)

adding (1) and (2)

2a = -p -p/3

=>2a = -4p/3

=> a = -2p/3

putting a = -2p/3 in (2)

-2p/3 -b = -p/3

-b = p/3

b= -p/3

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