Question

If the sum of the roots of the following quadratic equation is equal to the product of its roots , then the value of k is 2x2 +(2k-1)x-(k-4) = 0​

Answer 1

Answer:

Compare given Quadratic equation

3x²+(2k+1)x-(k+5) = 0 with

ax²+bx+c=0, we get

a = 3 , b = (2k+1), c = -(k+5)

i ) Sum of the roots = -b/a

= -(2k+1)/3 ---(1)

ii) product of the roots = c/a

= -(k+5)/3 ----(2)

According to the problem given,

-(2k+1)/3 = -(k+5)/3

=> 2k+1 = k+5

=> 2k-k = 5-1

=> k = 4

Therefore,

k = 4