Question

if the sum of the roots of the quadratic equation (m+1)x^2 +(2m +3 )x + (3m+4)=0 is -1.
find product of roots​

Answer 1

Answer:

Product Of roots is 2.

Step-by-step explanation:

Explained In image.

Thank You.

Follow if the answer helped you.

Answer 2

The product of the roots is 2

Given:

The given equation (m+1)x² +(2m +3 )x + (3m+4) = 0

The sum of the roots of the quadratic equation is - 1

To find:

The product of the roots.

Solution:

Step 1 of 2:

The given quadratic equation, (m+1)x² +(2m +3 )x + (3m+4) = 0

a = m + 1

b = 2m + 3

c = 3m + 4

Sum of the roots is - 1

Sum of the roots = $-\frac{b}{a}$

$-\frac{2m+3}{m+1}$ = - 1

2m + 3 = m + 1

2m - m = 1 - 3

m = - 2

Step 2 of 2:

Product of the roots  = $\frac{c}{a}$

Product of the roots  = $\frac{3m+4}{m+1}$

m = - 2

Product of the roots = $\frac{3(-2)+4}{(-2)+1}$

Product of the roots = $\frac{-6+4}{-2+1}$

Product of the roots = $\frac{-2}{-1}$

Product of the roots = 2

The product of the roots is 2