If the sum of the sequence 1, 6, 11, 16 ........ x is 148, then find the value of x.
Plzz answer fast!! Class 10
Chapter : AP
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We have, AP 1,6,11,16,.............x
a=1 and d = 5
Let an = x
a + (n-1)d = x
1 + 5n-5 = x
so, 5n - 4 = x
n = x+4/5 .........................................(1)
We have, Sn = 148
n/2[a+an] = 148
n/2[1+x] = 148
so, n[1+x] = 296
By using (1)
x+4/5[1+x] = 296
[x+4](x+1) = 1480
so, x²+5x+4 = 1480
so, x²+5x - 1476 = 0
so, x² + 41x- 36x - 1476 = 0 [By splitting middle term]
= x(x+41) -36(x+41)
so, x = 36,-41
But according to AP x couldn't be negative so, x = 36
a=1 and d = 5
Let an = x
a + (n-1)d = x
1 + 5n-5 = x
so, 5n - 4 = x
n = x+4/5 .........................................(1)
We have, Sn = 148
n/2[a+an] = 148
n/2[1+x] = 148
so, n[1+x] = 296
By using (1)
x+4/5[1+x] = 296
[x+4](x+1) = 1480
so, x²+5x+4 = 1480
so, x²+5x - 1476 = 0
so, x² + 41x- 36x - 1476 = 0 [By splitting middle term]
= x(x+41) -36(x+41)
so, x = 36,-41
But according to AP x couldn't be negative so, x = 36
kunal0912:
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