if the sum of the series 24,20,16...... is 60,then the number of terms is
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a=24
d=a₂-a₁=-4
sₙ=60
n=?
sₙ=n/2(2a+(n-1)d)
60=n/2(2(24)+(n-1)-4)
120=n(48-4n+4)
120=n(52-4n)
30=13n-n²
n²-13n+30
n²-3n-10n+30 (by middle term)
n(n-3)-10(n-3)
(n-10)(n-3)
n=10,3
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