Question

If the sum of the series of the polynomial ky^2+2y-3k is equal to twice their product,find the value of k.
With steps..

Answer 1

Given quadratic polynomial f(t) = kt2  + 2t +3k

α,β are the roots of the quadratic polynomial then

α+β = -2/k and αβ = 3k/k

According to the condition α+β = αβ

-2/k = 3

∴ k = -2/3.

Answer 2

ky² + 2y + 3k

 a = k , b = 2 , c = 3k

Sum of the zeroes = -b/a = -2/k

Product of zeroes = c/a = 3k/k = 3

Both sum and product
-2/k = 3
k = -2/3


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