If the sum of the sqaures of zeroes of the polynomial 6x^2+x+k is 25/36 then find the value of x.
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let a and b are zeroes of polynomial 6x^2+x+k
and a^2+b^2=25/36
(a+b)^2-2×ab =25/36
(-1/6)^2-2×k/6=25/36
1/36-2k/6=25/36
k=25-1/-12
k=-17/6
now putting k=-17/6 in polynomial
we can find the value of x
and a^2+b^2=25/36
(a+b)^2-2×ab =25/36
(-1/6)^2-2×k/6=25/36
1/36-2k/6=25/36
k=25-1/-12
k=-17/6
now putting k=-17/6 in polynomial
we can find the value of x
Avi2002:
thank u so much
you welcome
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