if the sum of the square of three positive number is 14 and the sum of their product taking two at a time is 11 find the sum of the number
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Answer:
Step-by-step explanation:
a^2+b^2+c^2=14
ab+bc+ac=11
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)
=14+2(11)
=14+22
=36
a+b+c=6
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