if the sum of the square of zero of the polynomial 5 x square + 3 x+k is - 11/25 find the value of k
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We have p(x) = 5x^2 + 3x + k
Let, α and β are zeroes of p(x).
Now, α+β = coefficient of x/coefficient of x^2
⇒ α+β=-3/5
α*β = coefficient term/coefficient x^2
⇒ α*β = k/5
Now, α^2+β^2 = (α+β)^2 - 2α*β
⇒ 11/25 = (-3/5)^2 - 2k/5
11/25 = 9/25 - 2k/5
2k/5 = 9/25 - 11/25
2k/5 = -2/25
k = -1/5
Hope it helps you..
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