If the sum of the squares of the distance of a point from 3 coordinate axes is 36
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Answer:
Let (x,y,z) be the point.
Given sum of the squares of distance from point to the axes is 36.
⇒(x
2
+y
2
)+(y
2
+z
2
)+(z
2
+x
2
)=36
⇒2(x
2
+y
2
+z
2
)=36⇒x
2
+y
2
+z
2
=18
So the distance of the point from the origin is =
x
2
+y
2
+z
2
=3
2
Step-by-step explanation:
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