Question

If the sum of the squares of the distance of a point from 3 coordinate axes is 36

Answer 1

Step-by-step explanation:

Let (x,y,z) be the point.

Given sum of the squares of distance from point to the axes is 36. 

⇒(x2+y2)+(y2+z2)+(z2+x2)=36

⇒2(x2+y2+z2)=36⇒x2+y2+z2=18

So the distance of the point from the origin is =x2+y2+z2=32

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