If the sum of the squares of the zeroes of the polynomials 6x(square)+x+k is 25/36. Find the value of 'k'
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Sumof zeroes=-b/a=-1/6
Product of zero=c/a=k/6
then, square the both side
a²+b²=(a+b)²-2ab
25/36=(-1/6)²-2(k/6)
25/36-1/36)=-2*k/6
2/3=k/-3
k=-2
you have any problem.you will ask me.......
Product of zero=c/a=k/6
then, square the both side
a²+b²=(a+b)²-2ab
25/36=(-1/6)²-2(k/6)
25/36-1/36)=-2*k/6
2/3=k/-3
k=-2
you have any problem.you will ask me.......
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