if the sum of the squares of the zeros of the quadratic polynomial x2-8x+k is 46 find k
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Polynomials. If sum of the squares of zeroes of the quadratic polynomial p(x) = x2 – 8x + K is 40, find the value of K. Hence, K = 12. On dividing x3 – 3x2 + x + 2 by a polynomial g(x), the quotient and remainder, are x – 2 and –2x + 4, respectively.
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k=9
Step-by-step explanation:
Sum of the squares of zeroes=a²+b²=46
sum of squares =-coefficient of x/coefficient of x²=-(-8)/1
a+b=8
product of zeroes =ab=c/a=k
as we know the property,
(A+B)²=A²+B²+2AB
so, (a+b)²=a²+b²+2ab
(8)²=46+2k
64-46=2k
18=2k
k=9
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