Question

if the sum of the squares of the zeros of the quadratic polynomial x2-8x+k is 46 find k​

Answer 1

Answer:

Polynomials. If sum of the squares of zeroes of the quadratic polynomial p(x) = x2 – 8x + K is 40, find the value of K. Hence, K = 12. On dividing x3 – 3x2 + x + 2 by a polynomial g(x), the quotient and remainder, are x – 2 and –2x + 4, respectively.

Answer 2

Answer:

k=9

Step-by-step explanation:

Sum of the squares of zeroes=a²+b²=46

sum of squares =-coefficient of x/coefficient of x²=-(-8)/1

                                                                       a+b=8

product of zeroes =ab=c/a=k

as we know the property,

      (A+B)²=A²+B²+2AB

  so,     (a+b)²=a²+b²+2ab

            (8)²=46+2k

            64-46=2k

         18=2k

               k=9

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