Question

if the sum of the squares of two number which are consecutive multiple of 4 is 1360 find the number

Answer 1

I think it will help you

Answer 2

let the first number be n

then the second number will be n+4

A.T.Q

(n)^2 + (n+4)^2 =1360

n^2 + n^2 +16 = 1360

2n^2 = 1360 -16

n^2 = 1344 /2

n = underroot 672
= 25.92