Math, asked by ashutoshyadav2005, 10 months ago

if the sum of the squares of zeroes of polynomial x raise to the power 2-8x+k is 40. Find the value of k.

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Answered by Anonymous

$\huge\underline\bold\red{AnswEr}$

Let a and b are the zeroes of polynomial p (x)= x^2-8x+1. Sum of zeroes is given by :

: $a+b=\dfrac{-(8)}{1}=8 .....(1):$

ab=k

It is given that, a^2+b^2=40

It can be simplified as :

(a+b)^2-ab=40

From (1) we have,

: $8^2-2k=40\\\\2k=64-40\\\\k=12$

So, the value of k is 12.

Answered by srikanthn711

Answer:

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Polynomials. If sum of the squares of zeroes of the quadratic polynomial p(x) = x2 – 8x + K is 40, the value of K. Hence, K = 12.

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