If the sum of the squares of zeros of the polynomial 5x2 + 3x + k is
11
5, find the value of k.
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Answer:
sum of zeros=-3/5. let the roots are a,b
where
ab=k/5
so a^2+b^2=11
(a+b)^2-2ab=11 so
(-3/5)^2-2k/5=11
so 9/25-2k/5=11
so2 k/5=(9/25)-11
2k/5=-266/25
so k=-133/5 ( answer)
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