Question

If the sum of the squares of zeros of the quadratic polynomial

f(x) = x2 – 13x +2k-1 is 47 , find the value of k.

Answer 1

Answer:

A/Q

${ \alpha }^{2} + { \beta }^{2} = 47$

given,

$\alpha + \beta = 13 \: \: and \: \: \alpha \beta = 2k - 1$

now,

${ \alpha }^{2} + { \beta }^{2} = ( \alpha + \beta ) {}^{2} - 2 \alpha \beta = 47$

${13}^{2} - 2(2k - 1) = 47$

$169 - 2k + 2 = 47$

$2k = 171 - 47 = 124$

$k = 62$

Ans

Answer 2

Answer:

$k = 62$

Answer