Question

If the sum of the two numbers is 120 and their quotient is 5 then difference of the two numbers is

Answer 1

Hey,sup!

Let the two numbers be x and y.

As per the question,

1)x+y= 120.

2)x÷y= 5
=> x/y=5.
=> x=5y.

Putting value of x in 1.
=>x+y=120.
=>5y+y=120.
=>6y=120.
=>y=120/6= 20.
So, x = 5y= 5×20 = 100.

Therefore x-y = 100-20=80.

Hope it helps.

Answer 2

Given :

The sum of the two numbers is 120

The quotient of numbers = 5

To Find :

The difference of two numbers

Solution :

Let The first number = x

Let The second number = y

According to question

 Sum of numbers = 120

i.e   x + y  = 120        .........1

And

 quotient of numbers = 5

i.e    $\dfrac{x}{y}$ = 5

Or,   x = 5 y           ..........2

Solving eq 1 and 2

   ∵  x + y = 120

Or,   5 y + y = 120

Or,        6 y = 120

∴            y = $\dfrac{120}{6}$

i.e          y = 20

So, The second number = y = 20

Put the value of y into eq 2

∵  x = 5 y

Or,   x = 5 × 20

∴     x = 100

So, The First number = x = 100

Hence, The First number is 100  and The second number is 20  . Answer