Question

If the sum of the zero of the quadratic polynomial f(t) = kt^2 +2t+ 3k is equal to their product, find the value of k

Answer 1

Answer:

-2\3

Step-by-step explanation:

Let F(t)= kt2 +2t +3t

there, a=k

b=2

c=3k

Give

sum of zeros= -b/c

alpha+beta=-2/k

product of zeros=c/a

alpha*beta=3k/k

Now,

alpha+beta=abpha*beta

3=-2/k

k=-2/3

so, the value of K= -2/3