if the sum of the zeroes of a polynomial f(x)= 2x3 -3kx2+ 4x-5 is 6 then find the value of k
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Answer:
f(x) = 2x3-3kx2+4x-5 is 6
f(6) = 2(6)^3-3k(6)^2+4(6)-5
= 2(216)-3k(36)+24-5
= 432-216k+19
= 451-216k
-451 = -216k
451/216 = k
2.087.. =k
2.1. = k
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