Question

If The sum of the zeroes of a polynomial p(x)=(a+1)x2+(2a+3)x+(3a+4) is -1,then find the product of it,s zeroes​

Answer 1

Answer:

Ok it's not that easy but let me explain this to you in a brief and short way.

p(x) = (a+1)×2+(2a+3)×x+(3a+4)

As,given sum of zeroes of polynomial p(x) = -1

Hence, x=-1

substitute -1 in the place of x in the polynomial p(x)

then you get ::

(a+1)×2+(2a+3)x+(3a+4)=0

2a+2+(2a+3)(-1)+3a+1=0

2a+2-2a-3+3a+1=0

3a=0

a=0/3( ZERO DIVIDIDED BY ANY NUMBER IS O)

a=0

Then,product of its zeroes is equal to "0"