Question

If the sum of the zeroes of f(t) = kt2 + 2t + 3k is equal to their product, find the value of k.

Answer 1

TOPIC :- QUADRATIC EQUATION

SUB-TOPIC :- Relation between roots and coefficient of a quadratic equation.

Concept used :- For a quadratic equation ax² + bx + c, sum of root = -b/a and product of roots = c/a.

STEPS

given, quadratic equation kt² + 2t + 3k

Sum of roots = -2/k

Product of roots = 3k/k = 3.

Given, sum of root = product of root

=> -2/k = 3

=> k = -2/3

Hope helped :)

Answer 2

Step-by-step explanation:

Sum of the zeroes = alpha + beta = -2/k

product of zeroes = alpha * beta = 3k/k = 3

alpha + beta = alpha * beta

-2/k = 3

-2/3 = k

k = -2/3