Question

if the sum of the zeroes of p(x) =(k^2 -14)x^2-2x -12 is 1,find k​

Answer 1

Ans=(k^2-14)π^2-2^π-2π-12

P(1)=(k^2-14)1^2-2×1-12

K=(2-14)1-2-12

K=(12)14-1

K=13-12

K=-1