If the sum of the zeroes of quadratic polynomial ky^2+2y-3k is equal to the twice of their product. find the value of k
Answers
Answered by
7
Answer:
HELLO
ky^2 +2y -3k=0
Sum of zeroes = -b/a
= -2/k
Product of zeroes = c/a
= -3k/k
=-3
According to the question,
Sum of zeroes = 2xproduct of zeroes
-2/k = -6
-6k=-2
K=1/3
hope it helps you mate.
please thank and mark my answer as brainliest.
@ ANUSHA ❤✌
Similar questions