Math, asked by shivam7s, 8 months ago

If the sum of the zeroes of quadratic polynomial ky^2+2y-3k is equal to the twice of their product. find the value of k​

Answers

Answered by Anonymous
7

Answer:

HELLO

ky^2 +2y -3k=0

Sum of zeroes = -b/a

= -2/k

Product of zeroes = c/a

= -3k/k

=-3

According to the question,

Sum of zeroes = 2xproduct of zeroes

-2/k = -6

-6k=-2

K=1/3

hope it helps you mate.

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@ ANUSHA

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