Question

if the sum of the zeroes of quadratic polynomial ky^2 +2y -3k is equal to their product .find the value of K​

Answer 1

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Answer 2

Answer:

Quadratic equation is

Ky² + 2y - 3k

Let α and β are its two zeros

The sum of zeros = α + β = -b/a

product of zeros = αβ =ab

Given condition. α + β = 2× αβ

-2 / k = -2×3k/k

-6k = -2

k =2/6

k = 1/3

hope you got it.

Step-by-step explanation:

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