Question

if the sum of the zeroes of the cubic polynomial is 2x3-kx2-8x-12 is -3/2 then find k

Answer 1

$2 \times 3 - k \times 2 - (8 \times12) = - \frac{ - 3}{2 } \\ \\ 6 - 2k - 96 = \frac{ - 3}{2} \\ - 96 + 6 - 2k = \frac{ - 3}{2} \\2( - 90 - 2k) = - 3 \\ - 180 + 3 = 4k \\ \frac{ - 177}{4} = k \\ 44 \times \frac{1}{4 } = k$