Question

if the sum of the zeroes of the polynomial 2x^3-3kx^2+4x-5is 6 then find the value of k ​

Answer 1

Answer:

k = 4

Step-by-step explanation:

Given :-

p(x) = 2x³ - 3kx² + 4x - 5

Sum of zeroes = 6

To find :-

Value of k

Solution :-

Let a, b, c be the zeroes then,

⟶ a + b + c = 6

So,

⇒ a + b + c = -b/a

⇒ -(-3k)/2

⇒ 3k/2 = 6

⇒ k/2 = 6/3

∴ k = 4

Answer 2

Answer:

k = 4

Step-by-step explanation:

Given

• p(x) = 2x³ - 3kx² + 4x - 5x
• Sum of zeros = α+β+γ = 6

To find

• value of k

Solution

α+β+γ = 6

-(-3k)/2 = 6

3k/2 = 6

3k = 6 × 2 = 12

k = 12/3 = 4

• Value of k = 4