Question

If the sum of the zeroes of the polynomial is 6, then the value of k is p(x)=2(x)2 - 3kx + 4

Answer 1

Answer:

Given:-

sum of the zeroes = 6

p(x)=2x²-3kx+4

=> here a=2

b= -3k

c=4

$sum \: of \: the \: zeroes \: = \: \frac{ - b}{a} \\ \rightarrow \: 6 = \frac{ - ( - 3k)}{2} \\ \rightarrow \: 6 = \frac{3k}{2} \\ \rightarrow \: k = 4$

hope it helps you.....✌✌

Answer 2

Answer:

Given:-

sum of the zeroes = 6

p(x)=2x²-3kx+4

=> here a=2

b= -3k

c=4

\begin{gathered}sum \: of \: the \: zeroes \: = \: \frac{ - b}{a} \\ \rightarrow \: 6 = \frac{ - ( - 3k)}{2} \\ \rightarrow \: 6 = \frac{3k}{2} \\ \rightarrow \: k = 4 \\ \end{gathered}

sumofthezeroes=

a

−b

→6=

2

−(−3k)

→6=

2

3k

→k=4