If the sum of the zeroes of the polynomial P of x=(k square -14)x square-2x-12is 1 then k takes the value (s)
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Answer:
Given f(x)=2x
2
+(p+3)x+5
we know that for ax
2
+bx+c=0 sum of roots =
a
−b
on comparing a=2,b=p+3,c=5
a
−b
=0 [given]
2
−(p+3)
=0
∴
p=−3
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