If the sum of the zeroes of the polynomial p(x)=(a+1)x^2+(2a+3)x+(3a+4) is -1 then find the product of its zeroes
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if we substitute the value of a then won't it be not defined ?
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a = a + 1
b = 2a + 3
c = 3a + 4
Sum of the zeroes = -b/a
= - ( 2a+3 )/ 3a+4 = -1
- ( 2a+3 )/ 3a+4 = -1
- 2a - 3 = (3a + 4) (- 1 )
- 2a - 3 = - 3a - 4
3a - 2a = - 4 + 3
a = - 1
Product of zeroes = c/a
= 3a + 4/ a + 1
= 3 (- 1) + 4/(-1) + 1
= -3 + 4/0
= 1/0
= not defined
b = 2a + 3
c = 3a + 4
Sum of the zeroes = -b/a
= - ( 2a+3 )/ 3a+4 = -1
- ( 2a+3 )/ 3a+4 = -1
- 2a - 3 = (3a + 4) (- 1 )
- 2a - 3 = - 3a - 4
3a - 2a = - 4 + 3
a = - 1
Product of zeroes = c/a
= 3a + 4/ a + 1
= 3 (- 1) + 4/(-1) + 1
= -3 + 4/0
= 1/0
= not defined
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