if the sum of the zeroes of the polynomial p(x)= is 6 then find the value of k
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Answer:
Given:-
sum of the zeroes = 6
p(x)=2x²-3kx+4
=> here a=2
b= -3k
c=4
\begin{gathered}sum \: of \: the \: zeroes \: = \: \frac{ - b}{a} \\ \rightarrow \: 6 = \frac{ - ( - 3k)}{2} \\ \rightarrow \: 6 = \frac{3k}{2} \\ \rightarrow \: k = 4 \\ \end{gathered}
sumofthezeroes=
a
−b
→6=
2
−(−3k)
→6=
2
3k
→k=4
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