If the sum of the zeroes of the polynomial P(x) = is 6, then the value of k is
a) 2 (b) 4 (c) 2 (d) -4
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Let a, b, c be the three zeros of p(x) ,then it is given that (a+b+c) = 6 . But from the equation p(x) = 0, we get, a+ b + c = 3k/2 which implies 3k/2 = 6 ==>k = 4 .
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