Question

If the sum of the zeroes of the polynomial p(x) = (k^2 − 14)x^2 − 2x − 12 is 1 then find the value of k. pls answer quick

Answer 1

Answer:

K^2-14/2= 1

K^2-14=2

K^2=2+14

=16

K^2=16

K= + or- 4

Step-by-step explanation:

Answer 2

QUESTION:

If the sum of the zeroes of the polynomial p(x) = (k^2 − 14)x^2 − 2x − 12 is 1 then find the value of k.

ANSWER:

GIVEN:

$p(x) = ( {k}^{2} - 14) {x}^{2} - 2x - 12$

Sum of zeroes = 1.

TO FIND :

Value of k?

Let

$\alpha \: and \: \beta \: are \: the \: zeroes \\ \: of \: the \: polynomial$

WE know that :

$sum \: of \: zeroes = \frac{ - coefficient \: of \: x}{coefficient of x2}$

Above polynomial is in the form of

$a {x}^{2} + bx + c = 0$

so,

a = (k^2-14)

b = -2

c = -12.

$\alpha + \beta = \frac{ - b}{a}$

$1 = \frac{ - ( - 2)}{ - 12}$

$1 = \frac{ - ( - 2)}{ {k}^{2} - 14}$

$1 = \frac{2}{ {k}^{2} - 14 } \\ {k}^{2} - 14 = 2\\ \\ {k}^{2} = 16 \\ k = +4 or -4$

FINAL ANSWER :

VALUE OF K IS +4 or -4.