If the sum of the zeroes of the polynomial p ( x) = (k^2-14)x^2-2x-12 is 1 then find the
value of k
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4
Answer:
k = 4,-4
Step-by-step explanation:
p(x)=(k²-14)x²-2x-12
let p,q are roots of given polynomials
sum of roots is -b/a
p+q=-b/a=1
b is coefficient of x =(-2),a is coefficient of x²=(k²-14)
=>-(-2)/k²-14=1
=>k²=16
=>k=4
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