Question

If the sum of the zeroes of the polynomial pix) = kx²+2x+3k is equal to their product then
find two value of k'.
​

Answer 1

Answer: k = -2/3

Step-by-step explanation:

Kx²+2x+3k = 0

a = k , b = 2 , c = 3k

Sum of zeroes = -b/a

Product of zeroes = c/a

If, sum of zeroes = Product of zeroes then,

-b/a = c/a

- b = c

-(2) = 3k

-2 /3 = k

K = -2/3