Question

If the sum of the zeroes of the quadratic polynomial 3² - 6x +6 is 3, then find the value of k.

Answer 1

Answer:

Hey, wait a minute. Where is k in that polynomial?

Please write the question properly

Answer 2

$\sf\underline{Question:}$

If the sum of the zeroes of the quadratic polynomial 3kx² - 6x +6 is 3, then find the value of k. [I took that 3k is x square coefficient]

$\sf\underline{Answer:}$

sum of zeroes of quadratic polynomial

$\alpha + \beta = \frac{ - b}{a}$

$= \frac{ - ( - 6 )}{3k} = \frac{6}{3k}$

Given that the sum of zeroes is 3

$\frac{6}{3k} = 3$

$6 = 9k$

$k = \frac{6}{9} = \frac{2}{3}$

Have a good evening!