Question

If the sum of the zeroes of the quadratic polynomial 3x2 -kx +6 is 3, then find the value of k ?

Answer 1

Answer:

ANSWER

3x2−2=0x2=32x=±32

Sum of roots =−ab=30=0

32+(−32)=0

Product of roots =ac=3−2

Product 32×(−32)=−32

Answer 2

k = 9

Step-by-step explanation:

In a general quadratic equation of form

ax^1 + bx + c = 0, sum of roots are by -b/a

In the given quadratic equation,

3x^2 - kx + 6 = 0

a = 3, b = -k, c = 6

Sum of roots = -b/a = -(-k)/3 = k/3

and sum of roots is given 3

k/3 = 3

k = 9